The Distribution Law and Why Extraction in Portions Works Better

Physical Chemistry · Equilibria

The Distribution Law and Why Extraction in Portions Works Better

A short derivation that settles a practical question — is one large extraction better than several small ones, and by how much.

BSc & MSc · Physical Chemistry · Concept

The short answer: A solute distributes between two immiscible solvents in a fixed ratio at constant temperature. Working through the arithmetic shows that several small extractions remove far more solute than one extraction with the same total volume — which is why laboratory procedure always specifies portions.

The law

When a solute is shaken with two immiscible solvents, it distributes so that the ratio of its concentrations is constant at a given temperature:

KD = Corganic / Caqueous

KD is the distribution coefficient. The law holds provided the solute exists in the same molecular form in both phases — a condition that matters, because association or dissociation in one phase breaks it.

Where the solute dimerises in one solvent, the simple ratio is not constant. Instead the concentration in that phase varies as the square of the other, and the observed deviation is used to detect the association. Questions that supply distribution data failing to give a constant ratio are asking you to infer association or dissociation, not to conclude the experiment was faulty.

The multiple extraction formula

Start with mass W of solute in volume V of water, and extract with volume L of organic solvent n times. The mass remaining after n extractions is

Wn = W [ V / (V + KDL) ]n

The bracket is less than one, so raising it to a higher power removes more solute. That is the entire reason repeated extraction wins.

Worked comparison

Suppose KD = 2, the aqueous volume is 100 mL, and 100 mL of organic solvent is available in total.

StrategyCalculationFraction remaining
One extraction with 100 mL[100/(100 + 2×100)]10.333
Two extractions with 50 mL each[100/(100 + 2×50)]20.250
Four extractions with 25 mL each[100/(100 + 2×25)]40.198

Same total solvent, substantially better recovery. The improvement diminishes as portions get smaller, so in practice three or four portions is the usual compromise between efficiency and effort — a point worth stating when a question asks for a recommendation rather than a number.

Why extraction is useful analytically

Because KD differs between solutes, extraction separates them. Two substances with distribution coefficients far apart can be cleanly separated in a few extractions; ones with similar coefficients require many stages, which is the principle behind countercurrent distribution and, ultimately, partition chromatography.

Chemical manipulation widens the difference deliberately. Converting a solute to an ionic form usually confines it to the aqueous phase, while its neutral form partitions into the organic. So adjusting pH can move an acidic or basic compound between phases at will, which is how acidic, basic and neutral organic compounds are separated in a standard workup.

Extraction with a complexing agent

A metal ion is normally too hydrophilic to enter an organic solvent. Adding a chelating agent that forms a neutral, lipophilic complex changes that entirely, and the complex extracts readily. Selectivity comes from choosing conditions — particularly pH — where only the wanted metal forms the extractable complex.

This is the basis of many separations, including the lanthanide separations that would otherwise be extremely difficult.

Frequently asked questions

Why must the solute be in the same form in both phases?

Because the law equates concentrations of the same species. If the solute dimerises in one phase, the species are different and the simple ratio no longer holds.

Does temperature affect the distribution coefficient?

Yes, since it is an equilibrium constant. It must be quoted at a stated temperature, and comparing values measured at different temperatures is invalid.

Why not use very many tiny extractions?

Because the returns diminish sharply while the labour and losses from transfers increase. Three or four portions capture most of the available benefit.

How is pH used to control extraction?

By converting a compound between its neutral and ionic forms. The neutral form partitions into the organic phase; the ionic form stays aqueous. Adjusting pH therefore switches a compound between phases selectively.

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