Magnetic Properties: When the Spin-Only Formula Works and When It Fails

Inorganic Chemistry · Magnetism

Magnetic Properties: When the Spin-Only Formula Works and When It Fails

A formula that fits first-row complexes well and lanthanides badly, and the reason for the difference is instructive.

BSc & MSc · Inorganic Chemistry · Concept

The short answer: The spin-only formula gives the magnetic moment from the number of unpaired electrons alone. It works when the orbital contribution is quenched by the ligand field, which is usually the case for first-row transition metals. It fails for lanthanides, where the f orbitals are shielded and the orbital contribution survives.

The spin-only formula

μ = √(n(n + 2)) Bohr magnetons

where n is the number of unpaired electrons. It gives a fixed value for each n, so measuring the moment identifies n directly.

Unpaired electronsSpin-only moment
11.73
22.83
33.87
44.90
55.92

These five values are worth knowing, because a very large share of questions consists of matching a quoted moment to a number of unpaired electrons and hence to a spin state.

The chain of inference

Magnetic measurement is powerful because it starts a chain:

  1. Measured moment gives the number of unpaired electrons.
  2. That gives the electron configuration in the split d orbitals.
  3. That identifies the complex as high spin or low spin.
  4. Which tells you whether the ligand field splitting exceeds the pairing energy.
  5. Which places the ligand in the spectrochemical series.

Many exam questions run some portion of this chain, in either direction. Recognising which link is being asked for is most of the work.

Why the orbital contribution is usually absent

An electron has orbital angular momentum as well as spin, and in principle both contribute to the magnetic moment. In most first-row complexes the orbital contribution is quenched — suppressed by the ligand field.

Quenching happens because the ligand field fixes the orbitals in space. Orbital angular momentum requires the electron to be able to circulate freely between equivalent orbitals. A ligand field that makes those orbitals inequivalent in energy prevents that circulation, so the orbital contribution disappears. Where the field leaves suitable orbitals degenerate, some contribution survives — which is why certain configurations show moments slightly above the spin-only value.

Where the formula fails

SystemSpin-only formulaReason
First-row transition complexesUsually goodOrbital contribution quenched by the ligand field
Second and third rowLess reliableStronger spin–orbit coupling
LanthanidesFails badly4f orbitals shielded, so the field does not quench the orbital contribution

For lanthanides the full expression using the total angular momentum quantum number J must be used, which is precisely why term symbols matter for that series. The lanthanide case is therefore the standard example of the formula's limits, and it connects two topics.

Diamagnetism and paramagnetism

A substance with all electrons paired is diamagnetic and is weakly repelled by a magnetic field. One with unpaired electrons is paramagnetic and is attracted.

Diamagnetism is present in all substances, since all have paired electrons, but it is a much weaker effect and is masked wherever paramagnetism exists. So a measured moment of zero means no unpaired electrons, and any non-zero moment indicates paramagnetism.

Temperature dependence

For a simple paramagnet, susceptibility varies inversely with temperature — the Curie law. Plotting the reciprocal of susceptibility against temperature gives a straight line through the origin, and deviations from that line indicate magnetic interactions between centres rather than isolated ones.

Recognising that a non-zero intercept signals cooperative behaviour rather than experimental error is a higher-order point worth having.

Frequently asked questions

Why does the ligand field quench the orbital contribution?

Because orbital angular momentum requires electrons to circulate between equivalent orbitals. The field removes that equivalence, so the circulation is blocked.

Why does the formula fail for lanthanides?

Because the 4f orbitals are shielded by outer shells, so the ligand field barely reaches them and cannot quench the orbital contribution.

What does a moment slightly above the spin-only value indicate?

A residual orbital contribution, which occurs where the ligand field leaves suitable orbitals close enough in energy for partial circulation.

Can magnetic data distinguish tetrahedral from square planar?

Often yes for d8. A tetrahedral complex is paramagnetic with two unpaired electrons, while a square planar one is diamagnetic, so the measurement settles the geometry.

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