Skip to content
☰
HomeAdmissionCSIR NETChemical Science CoachingGATEChemical Science PreparationIIT JAMM.Sc Entrance CoachingCUET PGPost Graduate EntranceGeneral AptitudeNext batch 2 Jan 2027JEEMain & AdvancedNEETNCERT line by lineCUET UGDomain paperClass 11 ChemistryLive onlineClass 12 ChemistryLive onlineStudy Library📄Previous year papers171 official papers · JAM, NET, GATE, CUET🎞️Topic-wise decks32 PDF + PPTX decks, free🧾Build your own PDFChoose exam → topic → download📚Study materialUnit-wise notes for the batches📝Test papers 8–12School practice papers❓Dreamer's QuizWeekly chemistry quiz🧠Questions by topicRead online with verified answers🔎SearchTopics, courses and articles🧭Exam guidesSyllabus, pattern, eligibility✍️BlogChapter notes and PYQ analysis📘Books by ABPeriodic table and data bookGreat Home TutorPh.DAboutContactBlogsQ&A▶️ YouTubeEnquiryBook a free demoCall +91 92121 42427
Physical Chemistry

GATE Chemistry (CY) — Physical Chemistry — Miscellaneous previous year questions

17 questions · 2005 · all with verified answer · last checked 2026-11-06

Make a PDF of this topic

Q1 · 2005-2021 · 2 marks

Which of the following statements is NOT correct for a catalyst?
  • (a) It increases the rate of a reaction
  • (b) It is not consumed in the course of a reaction
  • (c) It provides an alternate pathway for the reaction
  • (d) It increases the activation energy of the reaction
Show answer

Answer: (d)

Report an error in ABC26PH0338

Q2 · 2005-2021 · 2 marks

The value of the rate constant for the gas phase reaction \mathrm{2NO_2 + F_2 \rightarrow 2NO_2F} is 38\ \mathrm{dm^3\,mol^{-1}\,s^{-1}} at 300 K. The order of the reaction is
  • (a) 0
  • (b) 1
  • (c) 2
  • (d) 3
Show answer

Answer: (c)

Report an error in ABC26PH0339

Q3 · 2005-2021 · 2 marks

The rate constant of two reactions as temperature T are k_{1}(T) and k_{2}(T) and the corresponding activation energies are E_{1} and E_{2} with E_{2}>E_{1}. When temperature is raised from T_{1} and T_{2}, which one of the following relations is correct?
  • (a) \frac{k_{1}(T_{2})}{k_{1}(T_{1})}=\frac{k_{2}(T_{2})}{k_{2}(T_{1})}
  • (b) \frac{k_{1}(T_{2})}{k_{1}(T_{1})}>\frac{k_{2}(T_{2})}{k_{2}(T_{1})}
  • (c) \frac{k_{1}(T_{2})}{k_{1}(T_{1})}\geq\frac{k_{2}(T_{2})}{k_{2}(T_{1})}
  • (d) \frac{k_{1}(T_{2})}{k_{1}(T_{1})}<\frac{k_{2}(T_{2})}{k_{2}(T_{1})}
Show answer

Answer: (d)

Report an error in ABC26PH0343

Q4 · 2005-2021 · 2 marks

For the reaction \mathrm{2X_3 = 3X_2}, the rate of formation of \mathrm{X_2} is:
  • (a) 3(-d[\mathrm{X_3}]/dt)
  • (b) \frac{1}{2}(-d[\mathrm{X_3}]/dt)
  • (c) \frac{1}{3}(-d[\mathrm{X_3}]/dt)
  • (d) \frac{3}{2}(-d[\mathrm{X_3}]/dt)
Show answer

Answer: (d)

Report an error in ABC26PH0344

Q5 · 2005-2021 · 2 marks

In a homogeneous catalytic reaction, 1.0 M of a substrate and 1.0\,\mu\mathrm{M} of a catalyst yields 1.0 mM of a product in 10 seconds. The turnover frequency (TOF) of the reaction (\mathrm{s}^{-1}) is
  • (a) 10^{-2}
  • (b) 10^{2}
  • (c) 10^{-3}
  • (d) 10^{3}
Show answer

Answer: (b)

Report an error in ABC26PH0345

Q6 · 2005-2021 · 2 marks

For the reaction given below, the relaxation time is 10^{-6}\,\mathrm{s}. Given that 10% of A remains at equilibrium, the value of k_1\left(\mathrm{s}^{-1}\right) is
A \underset{k_{-1}}{\stackrel{k_1}{\rightleftharpoons}} B
  • (a) 9 \times 10^5
  • (b) 10^{-5}
  • (c) 10^5
  • (d) 9 \times 10^{-5}
Show answer

Answer: (a)

Report an error in ABC26PH0346

Q7 · 2005-2021 · 2 marks

For the parallel first order reaction shown below Structure for this questionthe value of k_1 is 1 \times 10^{-4}\ \mathrm{s^{-1}}. If the reaction starts from X, the ratio of the concentrations of Y and Z at any given time during the course of the reaction is found to be \frac{[\mathrm{Y}]}{[\mathrm{Z}]} = \frac{1}{4}. The value of k_2 is:
  • (a) 1 \times 10^{-4}\ \mathrm{s^{-1}}
  • (b) 2.5 \times 10^{-5}\ \mathrm{s^{-1}}
  • (c) 4 \times 10^{-4}\ \mathrm{s^{-1}}
  • (d) 4 \times 10^{4}\ \mathrm{s^{-1}}
Show answer

Answer: (c)

Report an error in ABC26PH0348

Q8 · 2005-2021 · 2 marks

The specific rate constant of decomposition of compound is represented by
\text { Ink }=5.0-\frac{12000}{\mathrm{~T}}
The activation energy of decomposition for this compound at 300 K is
  • (a) 24 kcal/mole
  • (b) 12 kcal/mole
  • (c) 24 cal/mole
  • (d) 12 cal/mole Statement for Linked Answer Q. 54 and Q. 55: In the m vs T diagram for different phases of the same substance at one atmospheric pressure, the lines \mathrm{A}, \mathrm{B} and C compound to Structure for this question
Show answer

Answer: (c)

Report an error in ABC26PH0353

Q9 · 2005-2021 · 2 marks

For a given first order reaction, the reactant reduces to 1/4^{\text{th}} its initial value in 10 minutes. The rate constant of the reaction is:
  • (a) 0.1386\ \mathrm{min^{-1}}
  • (b) 0.0693\ \mathrm{min^{-1}}
  • (c) 0.1386\ \mathrm{mol\,L^{-1}\,min^{-1}}
  • (d) 0.0693\ \mathrm{mol\,L^{-1}\,min^{-1}} Structure for this questionStructure for this question
Show answer

Answer: (a)

Report an error in ABC26PH0356

Q10 · 2005-2021 · 2 marks

For a reaction involving two steps given below First step:
\mathrm{G \rightleftharpoons 2H}
Second step:
\mathrm{G + H \rightarrow P}
assume that the first step attains equilibrium rapidly. The rate of formation of P is proportional to
  • (a) [\mathrm{G}]^{1/2}
  • (b) [\mathrm{G}]
  • (c) [\mathrm{G}]^{2}
  • (d) [\mathrm{G}]^{3/2}
Show answer

Answer: (d)

Report an error in ABC26PH0360

Q11 · 2005-2021 · 2 marks

Consider the reaction, 2\mathrm{C}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{g})\rightleftharpoons 2\mathrm{CO}(\mathrm{g}) at equilibrium, The equilibrium can be shifted towards the forward direction by
  • (a) Increasing the amount of carbon in the system
  • (b) Decreasing the volume of the system
  • (c) Decreasing the pressure of the system
  • (d) Increasing the temperature of the system
Show answer

Answer: (c)

Report an error in ABC26PH0362

Q12 · 2005-2021 · 2 marks

The rate constant of a reaction is 1.25 \times 10^{-4}\ \mathrm{mol\,L^{-1}\,s^{-1}}. If the initial concentration of the reactant is 0.250 \mathrm{mol\,L^{-1}}, the total time (in second) required for complete conversion is ____
Show answer

Answer: 2000

Report an error in ABC26PH0370

Q13 · 2005-2021 · 2 marks

The dependence of rate constant k on a temperature T (in K) of a reaction is given by the expression
\ln k = [(-5000\ \mathrm{K})/T] + 10
The activation energy of the reaction (in \mathrm{kJ\ mol^{-1}}) is ____ (up to two decimal places)
Show answer

Answer: 41.57

Report an error in ABC26PH0371

Q14 · 2005-2021 · 2 marks

Under physiological conditions, the conversion of \mathrm{CO_2} to bicarbonate ion by carbonic anhydrase enzyme (MW = 30,000 \mathrm{g\,mol^{-1}}) has a turnover number of 4.00 \times 10^{5}\ \mathrm{s^{-1}}. The minimum amount of enzyme (in \mug) required to convert 0.44 g of \mathrm{CO_2} to bicarbonate ions in 100 seconds is ________ (up to two decimal places)
Show answer

Answer: 7.5

Report an error in ABC26PH0373

Q15 · 2005-2021 · 2 marks

According to Eyring state theory for a bimolecular reaction, the activated complex has
  • (a) no vibrational degrees of freedom
  • (b) vibrational degrees of freedom but they never participate in product formation
  • (c) one high frequency vibration that leads to product formation
  • (d) one low frequency vibration that leads to prodcut formation
Show answer

Answer: (c)

Report an error in ABC26PH0374

Q16 · 2005-2021 · 2 marks

Consider the following two parallel irreversible first order reactions at temperature T, Structure for this questionwhere k_1 and k_2 are the rate constants and their values are 5 \times 10^{-2} and 15 \times 10^{-2}\ \mathrm{min^{-1}} respectively, at temperature T. If the initial concentration of the reactant 'P' is 4\ \mathrm{mol\,L^{-1}}, then the concentration of product 'R' after 10 min of reaction is ____ \mathrm{mol\,L^{-1}}. (Round off to two decimal places) (Assume only P is present at the beginning of the reaction)
Show answer

Answer: 2.59

Report an error in ABC26PH0378

Q17 · 2005-2021 · 2 marks

In Freundlich isotherm, a linear relationship is obtained in the plot of (\theta = surface coverage and p = partial pressure of the gas)
  • (a) \theta vs p
  • (b) \ln(\theta) vs \ln(p)
  • (c) \ln(\theta) vs p
  • (d) \theta vs \ln(p)
Show answer

Answer: (b)

Report an error in ABC26PH0484

Prepare with the GATE batch

Every PYQ is discussed live in the batch. See the course or call +91 92121 42427.

Questions from the ABC Question Bank, typed from the official papers. A question whose answer is still under review is not shown.

WhatsappEnquire Now
📞 CallWhatsApp