Inorganic Chemistry

IIT-JAM Chemistry — Chemical Bonding previous year questions

19 questions · 2001–2005 · all with verified answer · last checked 2026-11-06

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Q1 · 2005-2022 · 2 marks

Hybridization of the central atoms in \mathrm{I}_{3}{ }^{-}, \mathrm{ClF}_{3} and \mathrm{SF}_{4}, respectively, are

(a) \mathrm{sp}^{3} \mathrm{~d}, \mathrm{sp}^{2} and \mathrm{dsp}^{2}
(b) \mathrm{sp}, \mathrm{sp}^{2} and \mathrm{sp}^{3} \mathrm{~d}
(c) \mathrm{sp}, \mathrm{sp}^{3} \mathrm{~d} and \mathrm{dsp}^{2}
(d) \mathrm{sp}^{3} \mathrm{~d}, \mathrm{sp}^{3} \mathrm{~d} and \mathrm{sp}^{3} \mathrm{~d} IIT JAM 2020

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Answer: (d)

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Q2 · 2005-2022 · 2 marks

The geometries of the species \left[\mathrm{Br}_{3}\right]^{+},\left[\mathrm{Br}_{3}\right]^{-}and \left[\mathrm{BrF}_{3}\right] are, respectively

(a) linear, trigonal bipyramidal and trigonal bipyramidal
(b) linear, linear and trigonal planar
(c) tetrahedral, trigonal bipyramidal and trigonal bipyramidal
(d) tetrahedral, trigonal pyramidal and trigonal planar IIT JAM 2019

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Answer: (c)

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Q3 · 2005-2022 · 2 marks

Correct trend in the bond order is

(a) \mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{-}
(b) \mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{2-}
(c) \mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{+}
(d) \mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}

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Answer: (d)

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Q4 · 2005-2022 · 2 marks

The bond order of \mathrm{N}_{2}{ }^{+}ion is ____ (Round off to one decimal place) IIT JAM 2018

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Answer: 2.5

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Q5 · 2005-2022 · 2 marks

The correct order of bond angles in \mathrm{BF}_{3}, \mathrm{NH}_{3}, \mathrm{NF}_{3} and \mathrm{PH}_{3} is

(a) \mathrm{BF}_{3}>\mathrm{NH}_{3}>\mathrm{NF}_{3}>\mathrm{PH}_{3}
(b) \mathrm{PH}_{3}>\mathrm{BF}_{3}>\mathrm{NF}_{3}>\mathrm{NH}_{3}
(c) \mathrm{PF}_{3}>\mathrm{PH}_{3}>\mathrm{NH}_{3}>\mathrm{NF}_{3}
(d) \mathrm{NH}_{3}>\mathrm{NF}_{3}>\mathrm{BF}_{3}>\mathrm{PH}_{3}

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Answer: (a)

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Q6 · 2005-2022 · 2 marks

The bond order of \mathrm{Be}_{2} molecule is

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Answer: 0

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Q7 · 2005-2022 · 2 marks

Effective nuclear charge for 3d electron in vanadium (atomic number =23 ) according to Slater's rule is

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Answer: 4.3

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Q8 · 2001-2022 · 2 marks

The intermolecular van der Waals potential is inversely proportional to \mathrm{r}^{6}. The corresponding force is proportional to

(a) \frac{1}{\mathrm{r}^{5}}
(b) \frac{1}{\mathrm{r}^{6}}
(c) \frac{1}{\mathrm{r}^{7}}
(d) \frac{1}{\mathrm{r}^{12}}

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Answer: (c)

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Q9 · 2005-2022 · 2 marks

The species having trigonal pyramidal shape is

(a) \mathrm{NO}_{3}{ }^{-}
(b) \mathrm{CO}_{3}{ }^{2-}
(c) \mathrm{BrF}_{3}
(d) \mathrm{SO}_{3}{ }^{2-} IIT JAM 2014

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Answer: (d)

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Q10 · 2005-2022 · 2 marks

Among the following, the isoelectronic pair is

(a) NO and CO
(b) \mathrm{O}_{2}{ }^{-}(superoxide anion) and \mathrm{NO}^{-}
(c) \mathrm{NO}^{+}and CO
(d) \mathrm{O}_{2}{ }^{-}(superoxide anion) and \mathrm{NO}^{+}

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Answer: (c)

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Q11 · 2005-2022 · 2 marks

Among \mathrm{Ar}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{HF} and HCl , the strength of interatomic / intermolecular forces follows the order:

(a) \mathrm{NH}_{4} \mathrm{Cl}>\mathrm{HF}>\mathrm{HCl}>\mathrm{Ar}
(b) \mathrm{HF}>\mathrm{HCl}>\mathrm{Ar}>\mathrm{NH}_{4} \mathrm{Cl}
(c) \mathrm{HCl}>\mathrm{Ar}>\mathrm{NH}_{4} \mathrm{Cl}>\mathrm{HF}
(d) \mathrm{Ar}>\mathrm{NH}_{4} \mathrm{Cl}>\mathrm{HF}>\mathrm{HCl} IIT JAM 2013

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Answer: (a)

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